Tessellate - S.T.E.M.S - Physics - School - Set 1 - Problem 1

Level 1

A uniform disc of mass M and radius R is lifted using a string as shown in the figure. Then ,

This problem is a part of Tessellate S.T.E.M.S.

its rate of change of angular momentum is M g R MgR its angular acceleration is g R \dfrac{g}{R} its linear acceleration is g 2 \dfrac{g}{2} upward its linear acceleration is g g downward

Writabrata Bhattacharya by Writabrata Bhattacharya , 22, India

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1 solution

Will van Noordt
Dec 30, 2017

Calculate the net torque on the body:

T = R ( 3 M g 2 − M g 2 ) = M g R T = R(\frac{3Mg}{2}-\frac{Mg}{2}) = MgR

Torque is the rate of change of angular momentum.

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This option is technically incorrect. Torque/Angular Momentum is always defined about some axis/point. In this case, the axis passing through the center and perpendicular to the plane of the disc gives net torque as MgR. Regards

Math Geeks - 3 years, 4 months ago

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Good observation!

Will van Noordt - 3 years, 4 months ago

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