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I did it by this way.
The total number of squares in this 1 5 × 1 5 grid is 1 5 × 1 5 + 1 4 × 1 4 + 1 3 × 1 3 + 1 2 × 1 2 + 1 1 × 1 1 + 1 0 × 1 0 + 9 × 9 + 8 × 8 + 7 × 7 + 6 × 6 + 5 × 5 + 4 × 4 + 3 × 3 + 2 × 2 + 1 × 1 which is equal to 1 2 4 0 @megh choksi
No. of 1 cm squares from any corner is 15×15 not 1×1.
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No. of 15 cm squares from any corner is 1×1 not 15×15.
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I mean to say of area 1 c m 2 . Thank you big mistake edited
Using binomial theorem for (2n+1)(n+1)n/(6)
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Number of 1 c m 2 squares from any corner is 1 × 1 = 1 2
Number of 2 c m 2 squares from any corner is 2 × 2 = 2 2
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Number of 1 5 c m 2 squares from any corner is 1 5 × 1 5 = 1 5 2
Total = 1 2 + 2 2 + . . . . . . . . . . . . . . . . . . . 1 5 2 = 6 1 5 . 1 6 . 3 1 = 1 2 4 0
we will not multiply it by 4 since we have covered all the area.