Evaluate the limit above. Give your answer up to the fourth decimal place.
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Relevant wiki: Riemann Zeta Function
L = n → ∞ lim k = 1 ∑ n k 2 1 ∫ − ∞ ∞ e − x 2 d x = k = 1 ∑ ∞ k 2 1 ⋅ 2 ∫ 0 ∞ e − x 2 d x = ζ ( 2 ) ⋅ π erf ( ∞ ) = 6 π 2 ⋅ π ⋅ 1 ≈ 2 . 9 1 5 6 Since the integrand is even. Error function erf ( z ) = π 2 ∫ 0 z e − t 2 d t Riemann zeta function ζ ( s ) = n = 1 ∑ ∞ n s 1