Tetrahedron inscribed and circumscribed ellipsoids volumes ratio

Geometry Level pending

Given an arbitrary tetrahedron, if V 1 V_1 is the maximum volume of an inscribed ellipsoid inside it (i.e. ellipsoid inside it touching its four faces), and V 2 V_2 is the minimum volume of a circumscribed ellipsoid outside it (i.e. ellipsoid passing through its four vertices), then V 2 = k V 1 V_2 = k V_1 , for a positive integer k k . Find k k .


The answer is 27.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Hongqi Wang
Dec 6, 2020

I got the answer from regular tetrahedron: line mid point E of a side CD and two opposite vertexes A, B respectively then get a △ having 3 sides 3 : 3 : 2 \sqrt 3 : \sqrt 3 : 2 . Obviously the orthocenter O of this △ is the center of tetrahedron. Then we can get that: the length from center O to vertex A is O A = 6 4 OA = \frac {\sqrt 6}{4} , and from center O to face's center H is O H = 6 12 OH = \frac {\sqrt 6}{12} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...