Below are five free tetrominos "I", "O", "L", "T", and "Z".
What is the minimum number of complete sets of these tetrominos (each set contains all five of them) needed to form a rectangle without gaps?
Rotation and reflections are allowed.
If it will never form a rectangle, no matter the number of sets, enter the answer as .
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If we consider a chess board colouring, it is obvious that the I,O,L and Z tetrominos each cover 2 white and 2 black squares. However, the T tetromino covers 3 of one colour and 1 of the other. A rectangle must have the same number of black and white squares, meaning 1 complete set isn't possible.
2 complete sets are possible, as shown below (note that this design isn't unique)