AM and GM

Algebra Level 2

a , b , a,b, and c c follow an arithmetic progression . Denote x x as the geometric mean of a a and b b , and y y the geometric mean of b b and c . c.

Find the arithmetic mean of x 2 x^2 and y 2 y^2 in terms of a , b , a,b, and/or c c .

a 2 a^2 b 2 b^2 c 2 c^2 None of the above

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Ram Mohith
May 31, 2018

x x is the geometric mean between a a and b x 2 = a b b \implies x^2 = ab

y y is the geometric mean between b b and c y 2 = b c c \implies y^2 = bc

a , b , c a,b,c are in A.P 2 b = a + c \implies 2b = a + c

A.M of x 2 , y 2 = x 2 + y 2 2 x^2, y^2 = \large\frac{x^2 + y^2}{2}

a b + b c 2 = b ( a + c ) 2 = b × 2 b 2 = b 2 \implies \large\frac{ab + bc}{2} = \frac{b(a + c)}{2} = \frac{b \times 2b}{2} = b^2

Ralph James
May 1, 2016

Let d d be the common difference for these terms. You get a , a + d , a + 2 d a, a + d, a + 2d by the definition of AP.

x = ( a ) ( a + d ) = a 2 + a d \implies x = \sqrt{(a)(a + d)} = \sqrt{a^2 + ad}

y = ( a + d ) ( a + 2 d ) = a 2 + 2 d 2 + 3 a d \implies y = \sqrt{(a + d)(a + 2d)} = \sqrt{a^2 + 2d^2 + 3ad}

x 2 + y 2 2 = a 2 + a d x 2 + a 2 + 2 d 2 + 3 a d y 2 2 = 2 a 2 + 4 a d + 2 d 2 2 = ( a + d ) 2 = b 2 \dfrac{x^2 + y^2}{2} = \dfrac{\underbrace{a^2 + ad}_{x^2} + \underbrace{a^2 + 2d^2 + 3ad}_{y^2}}{2} = \dfrac{2a^2 + 4ad + 2d^2}{2} = (a + d)^2 = \boxed{b^2}

Skanda Prasad
Oct 19, 2017

@Skanda Prasad , i LOVE your description :)

A Former Brilliant Member - 3 years, 7 months ago

Log in to reply

Hi, Lucia...Thanks a lot!

Skanda Prasad - 3 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...