That ball is gone! (part 2)
(Assume a value for g of precisely 10 downwards.)
"Heywood swings and crushes one towards South America! Tomlinson's gonna need a visa to catch that one. It is out of here and there ain't nothing left but a vapor trail! Vaughn continues to have problems with Heywood and the Yankees."
If the exit angle is 30 degrees (line drive) and the exit velocity is 1,000 , which is necessary to leave a vapor trail, what is the ball's maximum height in m, measured from a starting height of zero?
The answer is 12500.
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1 solution
The initial vertical component is 500 m / s , so it takes a total of 50 s for the ball to reach maximum height.
Since the deceleration is constant, we can use the average velocity of 250 m / s vertically upward over that span. multiplying by 50 s yields a max height of 12500 m.