What is the least positive multiple of that ends in ?
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We want to find the least k ∈ N such that 2 0 1 7 k ≡ 2 0 1 8 ( m o d 1 0 4 ) . But it is equivalent to 2 0 1 7 ( k − 1 ) ≡ 1 ( m o d 1 0 4 ) , so k − 1 is the multiplicative inverse of 2 0 1 7 modulo 1 0 4 , which is 4 3 5 3 . Therefore, k = 4 3 5 4 and the answer is 2 0 1 7 ⋅ 4 3 5 4 = 8 7 8 2 0 1 8 .