Find the smallest 3 digit narcissistic number that has a tens digit of 5.
This one is meant to be done by hand given the following hint:
This requires very little work if you guess and check in a smart way
Details:
A narcissistic number is a number that when its digits are individually raised to the n-th power and summed, they equal the original number.
Example:
4 0 7 = 4 3 + 0 3 + 7 3
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Begin with
1 0 0 a + 1 0 b + c = a n + b n + c n
Since our ten's digit is a 5, b = 5
We are trying to find the smallest possible, so start by guessing the smallest number: 1
1 0 0 ( 1 ) + 5 0 + c = 1 + 5 n + c n
1 4 9 + c = 5 n + c n
Obviously, n = 1 , 2 have no solutions.
Checking n = 3
c 3 − c − 2 4 = 0
( c 3 − 2 7 ) − ( c − 3 ) = 0
( c − 3 ) ( c 2 + 3 c + 8 ) = 0
Thus c = 3 and our smallest number is 1 5 3
Actually, a n − digit narcissistic number a 1 a 2 ⋯ a n satisfies:
a 1 a 2 ⋯ a n = k = 1 ∑ n ( a k ) n
So, you don't need to check with different n 's. For a 3 − digit narcissistic number, you cannot have any n other than 3 . If you have any other n , then it is a perfect digital invariant but not a narcissistic number. You can read more about it here .
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Let the number be x5y so that x^3+5^3+y^3=100x+5×10+y. Since it is smallest no. I guessed x to be 1 this gives 1+125+y^3=100+50+y. y^3-y=24 By hit and trial y=3 So the number is 153.