That's a lot of work!

Given the total mass of the pyramid and the height of the center of mass of the pyramid from previous questions, how much work in Joules did it take just to raise the stones of the pyramid off the ground to their current height? Use g = 9.8 m/s 2 g=9.8\text{ m/s}^2 .

Image credit: Wikipedia Gmanacsa


The answer is 2.5273E+12.

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1 solution

Ameya Salankar
Jun 5, 2014

We know the total mass of the pyramid ( 6877000000 k g 6877000000 kg ), the average height which they would be lifted ( = = centre of mass = 37.5 m = 37.5m ) & g = 9.8 m s 2 g = 9.8ms^{-2} .

Energy = m g h = 6877000000 × 9.8 × 37.5 = 2.5273 × 1 0 12 = mgh = 6877000000 \times 9.8 \times 37.5 = 2.5273 \times 10^{12}

\Rightarrow Total energy required is 2.5273 × 1 0 12 J \boxed{2.5273 \times 10^{12}}\text{J} .

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