2
x
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3
,
4
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5
The above are 2 integers, the smaller of which is 67.
What is the larger of the 2 numbers?
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First let 2x+3 =67 we get x=32 and then when we equate 4x-5=67 we get x=31/2 so 2x+3=67 is correct so according to the question 67 is the smaller number . When we equate x=32 in 4x-5 we get the value as 123 so 123 is the larger number
given smaller no is 67 by seeing it's that the smaller is 2x+3 then 2x+3 =67 soving we get x +32 now put this x in 4x-5 then it's equal to 123.
There are two possibilities: 4 x − 5 = 6 7 or 2 x + 3 = 6 7 If 4 x − 5 = 6 7 => x=18 a n d if 2 x + 3 = 6 7 =>x=32. Hence 3 2 > 1 8 ... we will choose x = 3 2 so 4 ∗ 3 2 − 5 = 1 2 8 − 5 = 1 2 3 . A n d t h e a n s w e r i s 1 2 3
First, 2x + 3 = 67, second 4x - 5 = 67.
Then, it gives us x = 32 or x = 18
If x = 18, then 2x + 3 = 39 and 4x - 5 = 67. This is false, because the other number is smaller than 67.
Thus, x = 32 must be the solution.
Then check it one by one.
2 * 32 + 3 = 67 and
4 * 32 - 5 = 123
And the correct answer is 123.
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Relevant wiki: Setting Up Equations
We either have 2 x + 3 = 6 7 or 4 x − 5 = 6 7 ,
which gives, x = 3 2 or x = 1 8 .
If x = 1 8 , then 2 x + 3 = 3 9 and 4 x − 5 = 6 7 , but this means that the other number is smaller than 67, so x = 1 8 is not a solution.
Thus, x must be 32.
And so, 2 x + 3 = 6 7 and 4 x − 5 = 1 2 3 .