That's not how you make ice cream

A sphere of negligible mass and radius r = 1 cm r = 1 \text{ cm} is placed inside a smooth hollow cone with semi-vertical angle α = π 6 \alpha = \dfrac{\pi}{6} .

Then, a liquid of density ρ = 1000 kg/m 3 \rho = 1000 \text{ kg/m}^{3} rises into the cone until no more liquid can possibly enter.

If the normal reaction force per unit length N λ N_\lambda between the sphere and the walls of the cone can be expressed in SI units as a b c \frac{a\sqrt{b}}{c} where a a , b b and c c are natural numbers with b b square free and a a and c c coprime, what is the value of a + b + c a+b+c ?

Details and Assumptions :

  • Assume that the sphere forms a tight seal with the walls of the cone and prevents the liquid from rising further

  • A small hole is present at the vertex of the cone to allow air to escape

  • Take g = 10 m/s 2 g = 10 \text{m/s}^2 .


The answer is 10.

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1 solution

Puneet Mangla
Dec 22, 2016

I balanced vertical component of normal reaction with bouyant force and I calculated the volume submerged by solid angle but I am getting answer 8 where am I wrong?

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