The 24 game - Part 2

$\large (9 \div 3) \times (11 - 3) = 3 \times 8 = 24$ .

$(11-(9/3))\times 3 = 8 \times 3 = 24$ .

[(11-9)^3] x3

((11-3) x 9) ÷ 3 = (8 x 9) ÷ 3 = 72 ÷ 3 = 24

3 x 9 = 27
27 - 3 = 24
24 + 1 - 1 = 24
Only kidding :) . the real method :

( 9/3 ) x ( 11 - 3) = 3 x 8 = 24

Since 72 / 3 = 24, we need to use the remaining 3 numbers, 3,9,11, to arrive at 72. Thus, 11 - 3 = 8, & 9 * 8 = 72.

((11 - 3) * 9) / 3 = 24

(9/3)(11-3)

(39÷3)+11=24

11 * 3 + 3 - 9

(11-3)*9 = 72 ; 72/3 = 24

• $3*(11-(9/3))$
• $(9/3)*(11-3)$
• $(11-3)/(3/9)$
• $((11-3)*9)/3$
• $(11-3)*(9/3)$
• $((11-3)/3)*9$
• $(9*(11-3))/3$
• $9/(3/(11-3))$
• $9*((11-3)/3$
• $(11-(9/3))*3$

(11-3)(9)=72, so, (72÷3)=24

(11-3)×(9÷3)

(3*11) - ( 9 /(3/3)) =

(11 - (9/3) ) * 3

9 x 3 - 3 = 24

The problem should mention that you use each number only once.

You can work out the problem methodically without depending on hit and trial by the following thought process: keep one of the numbers aside , let it be 3 . The following operations can be performed with the number 3 in order to get the result as 24 -> 1. 21+3 2. 27-3. 3. 8x3 4. 72/3 . By checking each option it is observed that only 3. And 4. Are feasible . You can get the 4th option by: ((11-3)x9)/3 . The 3rd option is obtained by: (9/3)x(11-3)

9(11-3) / 3 = 24

(11+3+3+9)-((11+3)-(3+9))

((11 - 3) x 9) / 3 = 24

(3x11) -9 =24

11 - 9 = 2

3 + -3 = 0

11(11 - 9) = 22

11(11 - 9) + 11 - 9 + 3 + -3 = 24

Here is way to do it but I don't know of a general test for it besides showing an example.

(11-3) x (9/3) = 24

(9÷3)×(11 ---3)=24

(11-3) x 9 /3 = 24

(11-3) * 9 / 3 = 24

3*11 -9 =33-9=24

$(11-3)\times \frac { 9 }{ 3 } =24$

24 = [(11 - 3) * 3]

9(11-3)/3=24

[(11-3)x9]/3

(11-3)*(9/3)=24

While not to the rules ... (11-9)^3 x 3 😊

(11x3)-9-3

(11-3)x9/3=8x9/3=72/3=24

LaTeX: $11_{3} \times (9 - 3) = 4 \times 6 = 24$

(3*11)-9=24

(11-3)*(9/3) = 24

9*(11-3)/3

((11-3) x 9)) / 3 = (8 x 9) / 3 = 72 / 3= 24

(11-3) x 9 / 3 = 24

11+9+3+3= 24

Looking at the others, my solution is complicated, but not nearly as complicated as some things on this site. (11-3)/3 9=24 11-3=8 8/3= $\frac{8}{3}$ $\frac{8}{3}$ 9= $\frac{72}{3}$ $\frac{72}{3}$ =72/3=24

((11-9)+3+3)•3

[11-3] x [9÷3]

(11-3) x (9/3) = 24

(39÷3)+11=24

( 9/3) X ( 11-3) 3X8=24 24=24

(11-3) x (9:3) = 8 x 3 = 24

3 x 3 = 33, 33 - 9 =24

9-3=6. 6+11=27. 27-3=24

(11-3) X (9/3) = 8 X 3 = 24

9/3 x (11-3) = 24

[(11 - 3) × 9]÷3

$\frac{39}{3}$ +11

((11 X 3)+(9 x 3)+ (9 + 3))/ 3=(33 + 27 + 12)/3=72/3=24

(11-3) * 9/3

(11 x 3) - 9 = 24

(11 - 3) X ( $\frac{9}{3}$ ) = 8 X 3 = 24

(11-3)*9/3

(9x3)-3+11-11=24

[(11-3)9]/3

11+9+3+3-(11-9)

(11-3)(9/3)=8 x 3=24

(11-3)x(9÷3)= 8x3=24

(11-3)×(9÷1/3)

{[(11-3)×9]÷3}

11+9+4+3-3

(11*3)-9=24

(9×3-4)×11/11

(9/3)(11-3)=24

(11-3)·(9/3)=24

11-3=8. 8*9=72. 72/3= 24

(11*(3/3))-9

(3/3)(4) = 4+9+11 = 24

9 / ( 3 / (11 - 3 ) ) = 9 / ( 3 / 8) = 24

It says can you form 24 using the four numbers and using any of the four operands and parentheses, of which I found two methods at deriving twenty-four: (11-3)(9÷3)=24, or 9(11-3)/3=24

If you don't have to use all 4 you can just do this: 11 x 3 - 9 = 24

If not: [(11 - 9) ^ 3] x 3

$\frac{9}{3}$ equals 3

11 minus 3 equals 8

8 times 3 equals 24

Going by the prime factorization of 24.

24 = 2x2x2x3 i.e. 2^3 x 3.

24 = (11-9)(11-9)(11-9) x 3 or

24 = (11-9)^3 x 3.

(11-3)9/3=24

24=8x3 and 11-3 = 8, so (11-3)x(9/3) = 24