An astronaut aged 25 years old went to space and traveled with a speed of 1.8*10^8 m/s. According to earth the astronaut arrive on earth after 30 years. What is his age now?
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The actual time is 1 − c 2 v 2 t 0 , where t 0 is the apparent time, by Special Relativity. This gives us 3 0 = 1 − ( 3 . 0 0 × 1 0 8 ) 2 ( 1 . 8 × 1 0 8 ) 2 t 0 . Solving, t 0 = 2 4 , so the final answer is 2 5 + 2 4 = 4 9 .