The amoeba Olympics

We know, $d=vt \Longrightarrow t= \frac {d}{v}$ where, d is the distance traveled, t is the time taken and v is the velocity...

From the question, we get,

$d = 1 mm = \frac {1}{1000} m$

$v = 10^{-5}m/s = \frac {1}{10^{5}}m/s = \frac {1}{100000}m/s$

$t = ?$

Plugging in the values in the formula, we get...

$t = \frac {\frac {1}{1000}m}{\frac {1}{100000}m/s} = \frac {100000}{1000}s = 100 s$

Hence, the required answer is, $\fbox {100}$

1 millimeter is $10^{-3}$ meters. The answer is therefore $\dfrac{10^{-3}}{10^{-5}}=\boxed{100\text{ seconds}}$

speed of amoeba= 1/100000 m/s

distance=1/1000 m

so time=distance/speed=100 seconds

$1mm = 0.1cm = 0.001m$

$\frac{0.001m}{10^{-5}m/s} = 100s$

From the velocity formula v =s/t, so t = s/v =0.001/ 10^-5 = 100 seconds

(10E-3) / (10E-5)

10^-5 m/s is also 10^-2 mm/s, which also converts to 1/100 of a millimeter per second. Thus, the time that would take an amoeba to run the "1 millimeter dash" is 100 seconds.

Time = Distance/Velocity

1mm=10E-3. time=distance/speed=10E-3/10E-5=100

10^-5 = 0,00001= {1}{100000} 1 mm = 10^-3 = 0,001 = {1}{1000}

Assim Temos Fração por Fração , Conservar a Primeira e Multiplica pela o Inverso da Segunda

{1}{1000} x {100000}{1} = {100000}{1000} = 100

We know that to calculate the time, we can use this popular formula :

S = V x t

So, we get t = S / V = 10 ^ -3 / 10 ^ -5 = 100 seconds

Time=Distance/Speed 1mm=0.001m Time=0.001/10^{-5}=100 seconds

Speed = Distance / Time , therefore Time = Distance / Speed. 1 millimeter = (10^-3)m. Thus, the time taken = (10^-3)/(10^-5) = 100 seconds.

Using $1mm = 10^{-3}m$ we can get $\frac {10^{-3}}{10^{-5}} = 100(s)$

Speed of Amoeba = v =10^(-5) m/s. Distance travelled by Amoeba = s = 10^(-3) m Therefore,time taken to cover the required distance = t = s/v =100 s.

A amoeba's speed = $10^{-5}$ meter ; Total Distance = $1$ millimeter = $10^{-3}$ meter ; So, Total time = $10^{-3}/10^{-5}$ = $100$

Speed given = 10^-5 m/s distance= 1 mm or 10^-3 m time= distance/speed time= 10^-3 / 10^-5 time=10^2=100

We know that, the velocity is defined in the physic that v = {frac}{s}{t} , v, s, t consequenly are velocity in meter/seconds, distance in meter, and time in seconds

So, the amoeba has velocity = 10^{-5} m/s and distance = 1 mm = 10^{-3} m, then the time is velocity x time = 100 seconds.