But I don't know all the values!

Geometry Level 1

cos ( 4 5 ) × cos ( 4 6 ) × cos ( 4 7 ) × × cos ( 13 5 ) = ? \cos(45^\circ) \times \cos(46^\circ) \times \cos(47^\circ) \times \ldots \times \cos(135^\circ ) = \ ?

0 0 1 -1 1 1 3 2 \frac { \sqrt { 3 } }{ 2 }

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6 solutions

In the product we find a term, which is cos ( 9 0 ) \cos(90^\circ) , and it is 0 0 . Hence, all the product is 0 \boxed{0} .

Moderator note:

Yes, simple standard approach.

Bonus question : What would the answer be if all the cosine functions are replaced by tangent functions instead?

Answer to Bonus question 1 is not defined since tan90 is not defined.

Dinesh Nath Goswami - 6 years ago

for bonus: undefined, to be specific minus infinity

Alakh Aggarwal - 5 years, 11 months ago

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How can it be - \infty if it's undefined? If that was the case, surely it would be defined.

Michael Fuller - 5 years, 11 months ago

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yeah true!! My mistake! :)

Alakh Aggarwal - 5 years, 11 months ago

It's undefined.

Animee World - 3 years, 3 months ago
Chris Brown
Apr 20, 2020

Eventually, everything will be multiplied by cos ( 90 ° ) = 0 \cos { \left( 90° \right) =0 } , and the rest will be multipled by 0 0 , so the value of the whole series is 0 0 .

Hadia Qadir
Aug 30, 2015

The answer is 0 because cos90 value is 0

Juan Valdiri
Jul 6, 2015

nice problem dude cos 90= 0 so pretty easy.

Hemanth Koundinya
Jun 17, 2015

since cos90 is 0 hence whole product is 0

Balaji Rajagopal
Jun 17, 2015

In that series cos 45 - cos 135 in between Cos90 is 0.

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