Not as easy as it looks (Part 2)

Bag X contains 4 red marbles, 7 blue marbles, and 8 green marbles. Bag Y contains 12 red marbles, 4 blue marbles, and 9 green marbles. Bag Z contains 13 red marbles, 5 blue marbles, and 7 gray marbles. I choose a bag at random, and a marble from the bag. Given that the marble is green, the probability that the marble was from Bag Z is p p . Compute 100 p \lfloor{100p}\rfloor .


The answer is 0.

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1 solution

There are no green marbles in bag Z , Z, so the probability that the green marble was from bag Z Z is 0 . \boxed{0}.

@Alex Li Fun question. I had already started with the conditional probability calculations when I re-read the question and saw "gray" where I had initially read "green". :)

Brian Charlesworth - 6 years, 1 month ago

This question was good, first I thought that gray was mistake.... and found answer to be 9 but when it went wrong, I thought that gray is deliberately given.

Nikola Alfredi - 1 year, 3 months ago

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