Let n be a natural number. Let ( a k ) k = 1 n be a permutation of the numbers { 1 , 2 , 3 , . . . n } . Let p n be the probability that a k = k for all 1 ≤ k ≤ n .
Find lim n → ∞ ln ( p n ) .
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! n = [ e n ! ] where [ . ] is the nearest integer function.
There's an elementary explanation of why this is in this wikipedia article: http://en.wikipedia.org/wiki/Random permutation statistics#Number of permutations that are_derangements
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This is a simple case of derangement , so n → ∞ lim p n = e 1 , answer is ln ( e 1 ) = − 1