The Answer May Surprise You

Let n n be a natural number. Let ( a k ) k = 1 n (a_k)_{k=1}^{n} be a permutation of the numbers { 1 , 2 , 3 , . . . n } \{1,2,3, ... n\} . Let p n p_n be the probability that a k k a_k \neq k for all 1 k n 1 \le k \le n .

Find lim n ln ( p n ) \lim_{n \to \infty} \ln(p_n) .


The answer is -1.

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2 solutions

Pi Han Goh
Mar 21, 2015

This is a simple case of derangement , so lim n p n = 1 e \displaystyle \lim_{n \to \infty} p_n = \frac {1}{e} , answer is ln ( 1 e ) = 1 \ln \left ( \frac 1 e \right) = \boxed{-1}

! n = [ n ! e ] !n=\left[ \frac { n! }{ e } \right] where [ . ] [.] is the nearest integer function.

Raghav Vaidyanathan - 6 years, 2 months ago
Richard Polak
Apr 3, 2015

There's an elementary explanation of why this is in this wikipedia article: http://en.wikipedia.org/wiki/Random permutation statistics#Number of permutations that are_derangements

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