The area of rectangle

Geometry Level 1

The 2 diagonals of this rectangle divide it into 4 triangles.

If the area of the shaded region is 42, then what is the area of the rectangle?

52 56 60 64

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

18 solutions

Otto Bretscher
Nov 29, 2018

The rectangle consists of eight congruent triangles, of area A A . We are told that 6 A = 42 6A=42 so A = 7 A=7 and 8 A = 56 8A=\boxed{56} .

Am I missing something?

Pieter van Veelen - 2 years, 6 months ago

Log in to reply

A question pertaining to the explanation or problem, maybe.

Chris Arsenault - 2 years ago

I think Q has been changed, so solutions should also be changed.

Mr. India - 2 years, 6 months ago

I did get the right answer but after 2 full pages of calculations hahaha Looking at ur answer and how simple it is made me think on how important to slow down first and look for out of the box solutions

Hady Kandil - 2 years, 6 months ago

Wrong my friend... what you said is true in the case of a square... not for a rectangle. Although the answer is correct the way you have solved it is definitely wrong.

Omar Ashwaq - 2 years, 6 months ago

Log in to reply

Take another look at it! This is third grade geometry! A diagonal bisects a rectangle into two congruent triangles.

Otto Bretscher - 2 years, 6 months ago

I think you’re thinking of symmetry. The diagonals are not lines of symmetry in all rectangles, but are in a square. However, the diagonals do indeed split the rectangle into two congruent shapes.

JoAnna Cobb - 2 years, 5 months ago

That's right, valid only for squares.

Sahil Barshikar - 2 years, 5 months ago

I agree it's 4 congruent rectangles that are then divided into 2 congruent triangles, and we can show that intersection of diagonal and perpendicular bisector will happen at the same point.

Yuliya Skripchenko - 2 years, 5 months ago

I got this answer right, but I'm in a very unconventional manner. I just thought of the lower common multiple of 42 and used it to divide 42 to get how many times it occurred. then I added it to the given area and I got my answer.

Oluwaseyi Lawal - 2 years, 5 months ago

Log in to reply

There might have been a bit of luck involved ;)

Otto Bretscher - 2 years, 5 months ago

I'm confused

Diego Pacios - 2 years, 5 months ago

I realised that the broad flat triangles can be reconstructed as the equilatera; triangles and that therefore the shaded area was three quarters of the whole - thus the answer to the final question is 42 + (42/3) = 42 +14 = 56.

Thomas Sutcliffe - 2 years, 5 months ago

My way is much simpler. I literally did 42 divided by 3 to find out the area of each triangle shaded: 42/3+14 42+14=56

Isobel Campbell - 2 years, 5 months ago

Log in to reply

Sorry my mistake: 42/3=14

Isobel Campbell - 2 years, 5 months ago

It's not immediately obvious that the three shaded triangles have the same area; that's what my solution is supposed to explain, graphically.

Otto Bretscher - 2 years, 5 months ago

I just now read the comment above mine.....

Isobel Campbell - 2 years, 5 months ago

Brillianttt

Kunda Pardhi - 2 years, 5 months ago

Since the diagonals divide them into four equal areas, I just calculated the answer backwards from the options. Let the unknown area be A. If option(A) is correct A=52-42, A= 10 =>Does that give us 4 equal areas? No. Now, with option(B), A=56-42, A=14 => Does that give us 4 equal areas? Yes. There’s our answer.

Jingle Jungle - 1 year, 11 months ago

I picked this comment thread because it has the highest interaction on this problem. I can’t seem to be able to post solutions of my own in a separate original thread on daily & weekly solutions, can only reply. Also, the latest weekly challenges that I have, are from last year, shouldn’t it be from this week or atleast this month/year. Explains why am I here and as is obvious that’s just me. Anyone knows what’s going on with my brilliant

Jingle Jungle - 1 year, 11 months ago
Oon Han
Dec 9, 2018

Since the diagonals of the rectangle split the whole rectangle into 4 equal parts, the shaded area is 3 quarters of the whole area.

3 A = 42 3A = 42 A = 14 A = 14 4 A = 56 4A = 56

Easiest solution to do in your head!

Andrew King - 2 years, 5 months ago

Why would these 3 areas equal to each other

Yuliya Skripchenko - 2 years, 5 months ago

Log in to reply

Take the triangle made by one of the diagonals. Since the other diagonal bisects it, the two triangles made from the original are equal.

Kevin Shi - 2 years, 5 months ago

Log in to reply

Says who? What theorems did you use? I think what you're looking for is the formula A=1/2 absin∆ where ∆ is the angle at the intersection point. Because sin(180-∆)= sin∆ and all sides are equal both areas are equal.

Lyuboslav Karmidzhanov - 2 years, 5 months ago

Each triangle is (1/2) base height. In one case we have (1/2)(a/2)(b/2). In the other, we have (1/2)(b/2)(a/2).

Edwin Gray - 2 years, 1 month ago

Pick any pair of those triangles and they all have the same base and height.

Lâm Lê - 9 months ago

You are brother

Kunda Pardhi - 2 years, 5 months ago
Zain Majumder
Dec 9, 2018

Let the length of the rectangle be l l and the width be w w . Then the area of the white triangle is 1 2 l w 2 = l w 4 \frac{1}{2}*l*\frac{w}{2} = \frac{lw}{4} .

The red region has area l w l w 4 = 3 4 l w = 42 l w = 56 lw-\frac{lw}{4}=\frac{3}{4}lw=42 \implies lw = \boxed{56} .

Jordan Cahn
Nov 29, 2018

Note: This problem has been changed by the Brilliant staff, my solution below is no longer accurate. Please see @Otto Bretscher 's solution.


Note that the height of one of the obtuse-angled triangles (call it h T h_T ) is half the height of the rectangle (call it h R h_R ). Furthermore, the bases of the obtuse-angled triangles are shared with the rectangle. Let A R A_R be the area of the rectangle and A T A_T be the area of one of the obtuse-angled triangles. Then A T = 1 2 b h T = 1 2 b 1 2 h R = 1 4 A R \begin{aligned} A_T &= \frac{1}{2}bh_T \\ &= \frac{1}{2}b\cdot\frac{1}{2}h_R \\ &=\frac{1}{4} A_R \end{aligned}

Thus, A R A T = 12.75 A R 1 4 A R = 51 4 3 A R 4 = 51 4 A R = 17 \begin{aligned} A_R-A_T &= 12.75 \\ A_R - \frac{1}{4} A_R &= \frac{51}{4} \\ \frac{3A_R}{4} &= \frac{51}{4} \\ A_R &= \boxed{17} \end{aligned}

Ana X Gss
Dec 12, 2018

It’s 42 divided by 3 plus 42 = 56

Spriha Basir
Dec 11, 2018

The diagonals divide the rectangle into 4 equal triangles.....hence each of the triangle of tha shaded part has the same area....

42÷3=14....14×4=56

By equal, you mean has the same area. They are not congruent.

Edwin Gray - 2 years ago
Edwin Gray
May 4, 2019

Let the rectangle have dimensions axb. The area of the left and right shaded triangles are (1/2)(a/2)(b/2). The area of the lower triangle is (1/2)(b/2)(a/2). The sum of the three triangles is (3/4)ab = 42, so ab = 56.

Al Z3B
Dec 31, 2018

4 triangles are the same area. 3 of them are 42. So each is 14. So area=14*4=56

Marco Paolo
Dec 16, 2018

42 divided by its occupied volume which is 75% gives the total volume of 56

Raul Pascual
Dec 15, 2018

If in the rectangle we named h= high and b= base, the total surface of the rectangle will be = bh

The sum of the area of the three triangles is 3A= 1/2h(b/2) + 1/2h(b/2) + 1/2b(h/2) = 3/4bh, and i f 3A=42 then 3A=3/4bh = 42, then bh = 4/3 x 42 = 56. And bh is the total surface of the rectangle.

Nice solution

Edwin Gray - 2 years ago
Lee Johnson
Dec 14, 2018

If each triangle is x, and 3x = 42, then x = 42/3 so, x = 14. we need 4x, therefore, 4x = 56

Alicia Smith
Dec 13, 2018

I just gested I’m a nood

Matthew Boersma
Dec 13, 2018

The rectangle is divided in half TWICE by lines connecting at opposite corners. This creates 4 triangles which must all have the same area (although the triangles are not identical in shape) 3/4 of the triangles are shaded in which equals an area of 42. Now we just solve this problem.

Step 1: 3/4 = 42/x ( multiply 3 × X + 42 ×4 )

Step 2: 3x = 168 ( divide both sides by 3 )

Answer: x = 56

nice solution

Edwin Gray - 2 years ago
Iyke Amafili
Dec 13, 2018

The rectangle divides into 4 equal triangles. 3 of the triangles have an area of 42. The solution is to find the area of the 4th triangle and add it to the 42. This sum will give you the total area of the rectangle.

So, since they are equal, Area of the 4th triangle is → 3A = 42; Therefore, A = 42/3 = 14 So, the area of the 4th triangle is 14 (which is the area of each triangle) Therefore, total area of rectangle is 14 × 4 or 42 + 14 = 56!

When you say the triangles are equal, you mean they have the same area. They are not congruent.

Edwin Gray - 2 years ago
Mukta Gadgil
Dec 12, 2018

So the area of 3 triangles is 42.

The area of all three triangles is the same, hence the fourth one will have the same area too.

Divide 42 by 3

42/3 = 14

Hence the area of the unshaded region is 14.

Add the area to the area of 3 triangles

14 + 42 = 56

Utsav Playz
Dec 12, 2018

Hey there is a very simple way to do this.

First the rectangle is divided into 4 parts which are all congruent and equal.

Out of these 3 parts of the rectangle are also congruent and equal and all these 3 triangle's area is 42. So, the area of 1 Triangle = 42/3 = 14

Now, As we can see clearly that 1 Triangle area is 14 but the to complete the triangle we need 4 triangles.

So, we can simply multiply it by 4 = 14 * 4 = 56

It is very simple to do if you use this unitary method

The 4 parts of the rectangle are not congruent, but they do have equal areas. A good example is a rectangle which is 6 by 8. Then it has 2 diagonals of 10 by the Pythagorean Theorem. If 8 is horizontal and 6 is vertical, Then the rectangle is divided into 4 triangles. The top and bottom are congruent and isosceles with area = (1/2) (8) (3) = 12. The left and right are congruent and isosceles with area = (1/2) (6) (4) = 12. Hope this helps.

Edwin Gray - 2 years ago
Magnus Käärik
Dec 11, 2018

Two diagonals of a rectangle divide it into four triangles which are equal. If we know that the area of 3 of these triangles is 42 then the area of 1 triangle is 42/3 which is 14. Since this rectangle is made of 4 equal triangles which have the area of 14 the area of the rectangle is 4 • 14= 56.

Good, but when you say that the triangles are equal, you mean in area, they are not congruent.

Edwin Gray - 2 years ago
Ralph Gatan
Dec 10, 2018

Easy as there are 3 shaded triangles and have an area of 42 . 42÷ 3 is 14 that means 4 triangles is 56 which is the whole rectangle logic people logic

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...