The area of the triangle, whose vertices are the cubic roots of Z
Algebra
Level
pending
It is known that (-2 + 2i) is one of the fourth roots of a complex number (Z). Then, in the Argand-Gauss plane, the area of the triangle, whose vertices are the cubic roots of Z, is equal to
10√ 3
8(√ 3 − 1)
12√ 3
4(√ 3 + 1)
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1 solution
3 ( − 2 + 2 i ) 4 ⇒ − 4 . Area [ RegularPolygon [ { 0 , 0 } , { 4 , π } , 3 ] ] ⇒ 1 2 3 . The second expression in English is What is the area of a regular polygon centered at the origin in a circle of radius 4 starting at angle π having 3 sides. The selected answer is the closest fit. One might argue that the area is imginary as it is the product of a real number and an imaginary number.