The average kinetic energy

Classical Mechanics Level 2

Fill in the blank:

Suppose the average kinetic energy of a gas molecule at 27 27 ∘ C ^\circ C is 2500 J . 2500 \text{J}.

The average kinetic energy at 227 227 ∘ C ^\circ \text{C} will be _____ \text{\_\_\_\_\_} .

Note: submit your answer to 2 decimal places


The answer is 4166.67.

Nazmus Sakib by Nazmus sakib , 24, Bangladesh

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1 solution

Nazmus Sakib
Sep 29, 2017

E 1 T 1 = E 2 T 2 \dfrac{E_1}{T_1}=\dfrac{E_2}{T_2}

or, E 2 = 2500 × 500 300 ≈ 4166.67 J E_2=\dfrac{2500\times 500}{300} \approx 4166.67 J

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