The basics of matrices.

Algebra Level 2

A n × n n \times n non-singular square matrix A A is said to be involutory if the matrix is its own inverse, i.e. iff A 2 = I n A^2 = I_n . Using this definition and taking determinants of both sides, we obtain

A 2 = 1 A 2 = 1 A = ± 1 |A^2| = 1 \implies |A|^2 = 1 \implies |A| = \pm 1

Hence, the determinant of an involutory matrix is always ± 1 \pm 1 .


Is the converse also true for all matrices?

That is if a matrix has determinant ± 1 \pm 1 , is the matrix always an involutory matrix?

The proof is flawed and not all involutory matrices have determinant ± 1 \pm 1 Yes No

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