The Befuddling Baker

Let the baker baked C cakes & (680-C) buns.

C - C * 3/4 = 680 - C - (680 - C)2/5

C/4 = 680 - C - 272 + 2C/5

C/4 + C - 2C/5 = 408

(5C + 20C - 8C)/20 = 408

17C = 8160

C = 480

So, the cakes amount was 480 & buns amount was 200.

& He made 480 - 200 = 280 more cakes than buns.

Let $C=$ number of cakes and $B =$ number of buns.

We have $1/4C = 3/5 B \Rightarrow C = 12/5B \Rightarrow B + C = 17/5B = 680 \Rightarrow B = 200 \Rightarrow C = 480$

So, the result is $\fbox{C - B = 280}$

Let the total no. of cakes be x

and the total no.of buns be y

from the information we get x+y =680 .....................................1

After selling 3/4 cakes and 2/5 buns , they were equal we get , 1/4 x = 3/5 y .....................................2

from equation 2 , x = 12/5 y

using this in 1 , 12/5 y+ y= 680

y = 200

x +y =680

x + 200 =680

x = 480

480 - 200 = 280

c+b=680.
1\4 c +3\5 b=2\4 c.
5c+12b=10c.
5c+12(680-c)=10c Solve the equation c=480 ,b=200 c-b=280

Let, x = cakes and y = buns

we know, x + y = 680................. (1)

(1-3/4)x = (1-2/5)y

(1/4)x = (3/5)y ................. (2)

solving the two equations we get

x = 480 and y = 200

so more cakes baked are 480-200 = 280

:) :) :)

C * 1/4 = B * 3/5

12 C = 5 B

ratio = 12/5

in that ratio,

the cakes and buns made are 480 and 200 respectively, so,

480- 200 = 280

the baker baked 280 more cakes than the buns.............

Hey yo,

let b = buns , c= cakes, since that 0.75 of cakes sold as well as 0.4 of buns are sold,

b + c = 680

b = 680 - c(1st),

as for 0.75c and 0.4b are sold, and they are equal after the selling,

0.25c = 0.6b

c = 2.4b(2nd),

by substituting (2nd) into (1st),

b = 680 - 2.4b

b = 680 / 3.4 = 200

c = 2.4(200) = 480 , cheking b + c = 200 + 480 = 680(so correct),

so cakes is > buns by = 480 - 200 = 280.....

Thanks....

Let $c$ be the number of cakes and $b$ for buns.

$c-\frac {3}{4}c=b-\frac {2}{5}b$

$\frac {1}{4}c=\frac {3}{5}b$

$5c=12b \Rightarrow \frac {c}{b}=\frac {12}{5}$

$\Rightarrow 12-5=7 \Rightarrow 7 \times (680/17) \Rightarrow 7 \times 40$

$280$ is the final answer

Let the no. of cakes=x and no. of buns=y

Then,x+y=680 (eq. 1 )

Now,no. of cakes he sold=3x/4

Cakes left with him=x-3x/4=x/4

No. of buns he sold=2y/5

Buns left with him=y-2y/5=3y/5

According to the question,

x/4=3y/5 (eq. 2)

Solving eq. 1 and 2,

we get x=480 and y=200

Therefore,no. of cakes=480 and no. of buns=200

No. of cakes more than buns=480-200=280

5 * ( 680 - x ) = 12 * X from this ... X = 200 so (680-200) = 480 cakes & 200 buns. 480 - 200 = 280

=> Total no. of cakes be C, and => Total no.of buns be B => we get C + B = 680

Let the baker baked C cakes & (680-C) buns, After selling 3/4 cakes and 2/5 buns ,

C - 3C/4 = (680 - C) - 2(680 - C)/5 C/4 = 680 - C - 272 + 2C/5 C/4 + C - 2C/5 = 408 (5C + 20C - 8C)/20 = 408 17C = 8160 C = 480

So, the cakes amount was 480 & buns amount was 200. & He made 480 - 200 = 280 more cakes than buns.