Find the remainder when x 2 5 5 5 + 2 5 5 5 is divided by x + 1
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Note that x + 1 ∣ x 2 n + 1 + 1 .
x 2 5 5 5 + 2 5 5 5 = x 2 5 5 5 + 1 + 2 5 5 4 ≡ 2 5 5 4
(That is when x>2554)
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Define f ( x ) = x 2 5 5 5 + 2 5 5 5 .
Then by the Remainder-Factor Theorem, f ( x ) divided by x + 1 is just f ( − 1 ) , since x + 1 = x − ( − 1 ) .
This gives us f ( − 1 ) = ( − 1 ) 2 5 5 5 + 2 5 5 5 = 2 5 5 4