The big brother cares for his little sister

Algebra Level 1

A big brother had 84 candies and his little sister had 48 candies. The big brother felt bad about her little sister so he wanted to give away some of his candies to her. But obviously since he was the big brother he wanted to be left with 10 candies more than her.

How many candies did he have to give away in order to be left with 10 candies more than her?


The answer is 13.

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3 solutions

Caleb Townsend
Mar 20, 2015

Every candy he gives her will decrease the difference between their amounts of candy by 2. 2. So to decrease the current difference of 36 36 to 10 , 10, he must give her 36 10 2 = 13 \frac{36-10}{2} = \boxed{13} candies. Surely he can be more generous to his little sister, he still has 71 71 candies!

Let x x be the candies the brother gave to the sister. When the brother gave x x candies, the sister recieved x x candies, but the brother wanted to be left with 10 10 more candies than the sister. Thus, we have:

The brother - the sister = 10

( 84 x ) ( 48 + x ) = 10 (84-x) - (48+x)=10

84 48 x x = 10 84 - 48 -x-x =10

36 2 x = 10 36 - 2x =10

2 x = 26 2x = 26

x = 13 x= \boxed{13}

Therefore, the brother gave 13 \boxed{13} candies to the sister.

Marlon Pasuquin
Mar 23, 2015

84 + 48 = 132

132 - 10 = 122

122/2 = 61

LS= 61 BB=71 (10 removed earlier)

84 - 71 = 13

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