A big brother had 84 candies and his little sister had 48 candies. The big brother felt bad about her little sister so he wanted to give away some of his candies to her. But obviously since he was the big brother he wanted to be left with 10 candies more than her.
How many candies did he have to give away in order to be left with 10 candies more than her?
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Let x be the candies the brother gave to the sister. When the brother gave x candies, the sister recieved x candies, but the brother wanted to be left with 1 0 more candies than the sister. Thus, we have:
The brother - the sister = 10
( 8 4 − x ) − ( 4 8 + x ) = 1 0
8 4 − 4 8 − x − x = 1 0
3 6 − 2 x = 1 0
2 x = 2 6
x = 1 3
Therefore, the brother gave 1 3 candies to the sister.
84 + 48 = 132
132 - 10 = 122
122/2 = 61
LS= 61 BB=71 (10 removed earlier)
84 - 71 = 13
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Every candy he gives her will decrease the difference between their amounts of candy by 2 . So to decrease the current difference of 3 6 to 1 0 , he must give her 2 3 6 − 1 0 = 1 3 candies. Surely he can be more generous to his little sister, he still has 7 1 candies!