The block has unreliable power, it will not move...

Three blocks A , B , C A,~B,C each of mass m m are arranged in pulley string system as shown in figure. All pulleys are massless and frictionless , while all strings are light and inextensible. Coefficient of kinetic friction between block A A and horizontal surface is equal to 0.5 0.5 and force P P acts on it. The value of p m g \dfrac{p}{mg} for which block C C does not move, is equal to?


The answer is 5.000.

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1 solution

Abhishek Sharma
Apr 14, 2015

We use Result 1 (see figure) repeatedly to get relation between acceleration of masses A A and B B .

Result 2 : As the pulleys are massless F N E T {F}_{NET} on pulleys is equal to 0.

We use Result 2 repeatedly to get relation between tension in string attached next to masses A A and B B .

Now we apply newton's second law of motion for masses A A , B B and C C .

P μ m g T = 4 m a 4 T m g = m a 2 T = m g P-\mu mg-T=4ma\\4T-mg=ma\\2T=mg

Solving above 3 equations simultaneously we get p m g = 5 \large \boxed{\frac{p}{mg}=5} .

Did the same way. It is a simple question of constraint

Aayush Patni - 6 years, 1 month ago

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