The "Brilliant" Set Part 2 Reposted

Given a Set A = { b , r , i , l , a , n , t } A=\{b,r,i,l,a,n,t\} . Then the number of ordered pairs ( P , Q , R , S ) (P,Q,R,S) which can be formed such that P A P \subseteq A , Q A Q \subseteq A , R A R \subseteq A , S A S \subseteq A And ( P Q ) ( R S ) = (P\cup Q)\cap (R\cup S)=\emptyset .

  • The answer is of the form m n m^{n} where m , n m,n are primes. Find m + n m+n
Also try The Brilliant Set


The answer is 14.

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1 solution

Parth Lohomi
Apr 28, 2015

Draw venn diagram, you will get that there are 7 7 spots where x x cannot go ( x A \forall x\in A ), so n ( A ) = 7 n(A)=7 thus total number of ordered pairs satisfying the relationship are 7 × 7 × 7 × 7 × 7 × 7 × 7 = 7 7 7\times 7\times 7\times 7\times 7\times 7\times 7 =7^7 m = n = 7 , m + n = 14 \therefore m=n=7,m+n=\boxed{14}

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