The Broken Diamond

Algebra Level 3

A diamond worth Rs. 640000 breaks into two pieces whose weights are in the ratio 5:3. If the value of the diamond varies directly with the square of its weight, then find the loss incurred due to breakage.

No loss incurred Rs. 340000 Rs. 300000 Insufficient data

View wiki
Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

when the diamond is broken, its value is:

( ( 5 8 ) 2 + ( 3 8 ) 2 ) ) ⋅ 640000 = 34 64 ⋅ 640000 = 340000 ⇒ ((\frac{5}{8})^2 + (\frac{3}{8})^2)) \cdot 640000 = \frac{34}{64} \cdot 640000 = 340000 \Rightarrow the loss incurred due to breakage = 640000 - 340000 = 300000 Rs \text{the loss incurred due to breakage = 640000 - 340000 =}\boxed{300000 \text{Rs}}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...