Car slipping on wet road

Classical Mechanics Level 1

A man drives a car on a wet road at a speed of 10 m/s 10 \text{ m/s} . He suddenly steps on the brake, which stops the car in 2 2 seconds. Find the coefficient of kinetic friction of the car.

Gravitational acceleration is g = 10 m/s 2 . g = 10 \text{ m/s}^{2}.

0.5 0.2 0.7 0.3

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Srinivasa Satti by Srinivasa Satti

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2 solutions

Paola Ramírez
Jan 4, 2015

Car aceleration is 0 m / s − 10 m / s 2 s = − 5 m / s 2 \frac{0 m/s-10 m/s}{2 s}=-5 m/s^2

Then F = m a F=ma , car will stop when F = F f r i c t i o n → m a = μ m g F=F_{friction} \rightarrow ma=\mu mg

μ = 5 m / s 2 10 m / s 2 = 0.5 \boxed{\mu= \frac{5 m/s^2}{10 m/s^2}=0.5}

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Harshit Motwani
May 19, 2014

v=u + at, v=0, u = 10, t = 2, a = 5. a=kg.k=1/2

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