For an even positive integer , we write down all the numbers on the squares of an chessboard.
Let be the sum of all the numbers written on black squares and be the sum of all the numbers written on white squares.
How many possible values of are there such that it is possible to achieve
Details and assumptions:
Each number appears exactly once on the board.
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Just see the solution at http://math.stackexchange.com/a/847993/27958. The reason why 1 0 3 S 1 = 3 2 n 2 ( n 2 + 1 ) implies 1 0 3 ∣ n is that there are no square roots of -1 modulo 103 (as it is a prime of the form 4k+3)