The chord did it

Geometry Level 3

In the circle G G , the midpoint of the radius F G FG is H H and A B E F AB\perp EF at H H . The semicircle with A B AB as diameter intersects E F EF in I I , line A I AI intersects circle G G in C C and line B I BI intersects the circle G G at D D , then chord B C BC is drawn.

If the radius of the circle G G is r r , then find length of chord B C BC .

r 3 2 \frac{r \sqrt{3}}{2} None of these choices r 2 r\sqrt2 r r

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Maria Kozlowska
Mar 8, 2016

A I = B I , A I B = 90 A = 45 AI=BI, \angle AIB = 90 \Rightarrow \angle A = 45

By Inscribed Angle Theorem:

B G C = 90 \angle BGC = 90

B G = C G = r , B C = 2 B G = 2 r BG=CG=r, BC = \sqrt{2} BG = \boxed{\sqrt{2} r}

Thank you for posting a solution to my question.

Rishabh Sood - 5 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...