Assume Jeff has three buckets coloured red, blue and green. There are tokens labelled 1 - 13 in the buckets. Jeff wants to arrange the tokens so that the following rules will not be broken: 1 must go in the red bucket. No bucket has 3 numbers where a number is the sum of the other 2. No bucket as 2 numbers where one is double the other. Is this possible?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
One possible solution is 1, 4, 7, 10, and 13 in the red bucket; 2, 3, 11, and 12 in the blue bucket; and 5, 6, 8, and 9 in the green bucket.