Component of force acting on electron
An electron with a speed of moves horizontally into a region where a constant vertical force of acts on it. The mass of the electron is Determine the approximate vertical distance the electron is deflected while it has moved horizontally.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
By using s = ut + 1/2 a t^2 - eqn 1 we can reach to ans. Since initial vertical speed is zero so the first term of equation goes 0 . so we are left with s = 1/2.a.t^2 . - eqn 2 Now, for t we get it from the time taken by the electron at 10^7 m/s to travel 30 mm distance horizontally which is t = (30 * 10^ -3. ) / (10^7) For a, we get it from a = F/ m =( 4.5 * 10^ -16 ) / ( 9.11 * 10^ -31 ) Put the value of t n a in eqn 2 and u ll get ans in metre . Multiply the ans by 10^3 and u ll get the desired ans of 1.5 mm .