The Cosmologist's Clock

It is the much too distant future. The universe has expanded and contracted a great many times. In 2015, a great physicist and inventor created a magnificently sturdy clock that could record the age of the universe for what seemed an eternity and even maintain its functions inside a singularity. However, when the heat death of the observable universe came in our period, the clock began to suffer an error. Every century, the clock would reset to zero and record again. If 201 5 201 6 2017 2015^{2016^{2017}} years have passed since it began to malfunction, what is the number shown on the clock?


The answer is 25.

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1 solution

Ivan Koswara
Aug 29, 2015

After removing the cruft, the question is simply "compute 201 5 201 6 2017 m o d 100 2015^{2016^{2017}} \mod 100 ". This is standard approach:

First, we can take the base modulo 100 100 , giving 1 5 201 6 2017 15^{2016^{2017}} .

Next, by Chinese Remainder Theorem we can split our task into two: modulo 4 4 and modulo 25 25 .

The latter is easy. 15 15 has 5 5 as divisor, so 1 5 201 6 2017 15^{2016^{2017}} has a lot of 5 5 s as divisor, in particular at least two of them. Thus 5 2 1 5 201 6 2017 5^2 | 15^{2016^{2017}} . But 5 2 = 25 5^2 = 25 , so 1 5 201 6 2017 m o d 25 = 0 15^{2016^{2017}} \mod 25 = 0 .

The former is also simple. Taking the base again modulo 4 4 gives ( 1 ) 201 6 2017 (-1)^{2016^{2017}} . Similar to above, 2016 2016 is even, so 201 6 2017 2016^{2017} is also even and thus ( 1 ) 201 6 2017 = 1 (-1)^{2016^{2017}} = 1 . Thus 1 5 201 6 2017 m o d 4 = 1 15^{2016^{2017}} \mod 4 = 1 .

Finding the unique integer in [ 0 , 100 ) [0,100) that is congruent to 1 ( m o d 4 ) 1 \pmod{4} and 0 ( m o d 25 ) 0 \pmod{25} is simple: it's 25 \boxed{25} .

What?!?!?! That's all it's asking? I thought there's some fancy time dilation / red shift astronomical mumbo jumbo in this question. (sigh)

Pi Han Goh - 5 years, 9 months ago

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Yes, that's all it's asking. To be honest I also find the question unsatisfactory (read: bad) for that reason, needing to figure out where the actual mathematical problem is.

Ivan Koswara - 5 years, 9 months ago

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