THE CRICKET MATCH

Algebra Level 2

In a cricket match, Team A scored 232 runs without losing a wicket. The score consisted of byes, wides and runs scored by two opening batsmen: Ram and Shyam. The runs scored by the two batsmen are 26 times wides. There are 8 more byes than wides. If the ratio of the runs scored by Ram and Shyam is 6:7, then the runs scored by Ram is:


The answer is 96.

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4 solutions

Shreyas Shastry
Mar 27, 2014

Let the number of runs scored by byes, wides and runs be x, y and z respectively:

x+y+z=232 -------- (i)

The runs scored by the two batsmen are 26 times the wides:

z=26y --------- (ii)

There are 8 more byes than wides:

x=y+8 -------- (iii)

Substituting equations (iii) and (ii) in equation (i),

we get, y=8,z=208

The runs scored by Ram and Shyam were in the ratio 6 : 7

Let the runs scored by Ram be 6r and by Shyam be 7r.

13r=208

=> r=16

Runs scored by Ram =16*6= 96

nice!!!! I also did the same way

Krishna Ramesh - 7 years, 1 month ago
Uday Islam
Apr 11, 2014

Runs by Batman : Wides

26:1

(We times by 8 to both of the numbers)

208:8

208 + Wides = Amount of runs in the match that were scored by the batsmen or by wides.

208 + 8 = 216

216 + (By runs [8 more than wides + amount of wides in the match) = Total Score of Team A

216 + (8+8) = Total Score of Team A

216 + 16 = 232

6:7 = Ram and Shyham’s Run Ratio

6+7=13

208/13 = 16

16 x 6 = 96

B+W+R=232
W+8+W+26 W=232 => W=8 therefore 26 8=6X+7X => X=16 therefore 6X=96 => runs scored by ram is 96

ram missed his century

Dinesh Grover - 6 years, 6 months ago

this question is same as the 'run of ram'

Dinesh Grover - 6 years, 6 months ago
Moshiur Mission
Mar 31, 2014

rams run = 6x & shyams run is 7x now W = 13x/26 = x/2 & B = x/2+8 so 13x+x/2+x/2+8 = 232 hence x = 16 ram run is 96

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