You have a 10 inch by 10 inch cube that is made up of little 1 inch by 1 inch cubes...
You paint the outside of the big cube red...
How many of the little cubes get painted?
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Answer
= 10³ – (10 – 2)³
= 10³ – 8³
= 1000 – 512
= 488
For this you can use the principle of inclusion-exclusion. There are 100 cubes on each face and there are 6 faces. 6 x 100 = 600. Then you subtract all the cubes you have counted twice (the edge cubes) because these are on more than one face. There are 10 cubes on each edge and 12 edges so there are 10 x 12 = 120 such cubes. 600 - 120 = 480. However, the corner cubes have now been subtracted too many times because they are on three edges. Therefore you need to add the eight corner cubes back on : 480 + 8 = 488 cubes. For more information about how the principle of inclusion - exclusion works see this note:
https://brilliant.org/discussions/thread/principle-of-inclusion-and-exclusion/
We can simply use the formula to determine the no. of small cubes in this cube to find out the no. of small cubes that have been painted ..... We can use the formula =
(n)^3-(n-2)^3
Here we have n=10,
(n)^3-(n-2)^ 3 = (10)^3-(10-2)^3 = 1000-512 = 488
it's not n^2 Here n^3
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Sorry, I now have corrected it. Thanks for notifying me.
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10^2=100 and 8^2 is 64 now 100-64 =36 not 488
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hmmm... i've corrected it i was influenced by the solution given thats why i wrote 2
Now its all correct thanks for notifying :D
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NOW no. 1 unit cubes on face A = 10 *10 = 100
face B = (let it be any adjacent face to A ) = 10 *10 -10(because 10 cubes of face A) = 90
face C = (let it be any adjacent face to B ) = 10 *10 -10 = 90
face D = (let the face be between A and C) = 10 *10 - 20 = 80
face E = ( let it be the top face) = 100 - 36 = 64
face F =(let it be the bottom face )= 100 - 36 = 64
NOTE : for better understanding refer to the image