The Curse of Reverse...Algebra

Algebra Level 1

{ x + 1 = y − 10 x = 9 z + x y = x 2 ! \large \begin{cases} x+1=y-10 \\ x = 9 \\ \dfrac{z+x}{y} = x^{2!} \end{cases}

Given the system of equations above, find z z and round it to the nearest thousandth.


The answer is 1611.000.

A Former Brilliant Member by A Former Brilliant Member

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1 solution

Zach Abueg
Apr 3, 2017

y = x + 11 = 20 y = x + 11 = 20

z = y x 2 ! − x = ( 20 ) ( 9 2 ) − 9 = 1611 z = yx^{2!} - x = (20)(9^2) - 9 = 1611

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