there is a number consisting of two digits,the digit in the units place is twice that of the tenths place ,and if two is subtracted from the sum of the digits,the difference is equal to 1/6 th of the number FIND THE NUMBER!
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Let unit digit=a ; tenth digit=b
so the number = 10a+b
b=2a ---( given)---1
(a+b)-2=(10a+b)/6 ---( given )---2
substitude Eqn:1 in Eqn:2
Then, a+2a-2=(10a+2a)/6
the number is 2x10+4=24