The Dishonest Dealer

Algebra Level pending

A dishonest dealer professes to sell his goods at cost price by using a false weight and thus gains 10 10 %. Find the heaviness of the weight he uses for weighing a kilogram (in grams).

910 920 940 900

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1 solution

Shreya R
Mar 18, 2014

To gain 10 10 %, let the weigh's weight be x x grams. So , x + 10 x+10 % o f 1000 = 1000 g r a m s of\quad 1000=1000grams . = > x + 100 = 1000 g r a m s . =>\quad \quad \quad x+100\quad =1000grams. Therefore, we get x = 900 g r a m s x=\ 900\ grams

Can anybody explain it properly.. yaa Shreya good try..

Narendra Jakhar - 7 years, 1 month ago

the phrase "gains 10%" is ambiguous. Do you mean gain in terms of profit, or gain in terms of the extra goods that he's left with?

Shi Feng - 7 years, 1 month ago

If we start with 1 cent per gram as cost price, the cost price of 900 grams would 9 dollars. The selling price would be 10 dollars. The profit amounts to 1/9=11.11%. If the weight used was 910 grams, The profit would be 90/910=9.89% (10% approx).

Please check the solution and comment.

John Writer - 7 years, 1 month ago

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