Two trains, each having a speed of 3 0 km/h , are headed at each other on the same straight track. A bird that can fly 6 0 km/h flies off the front of one train when they are 6 0 km apart and heads directly for the other train. On reaching the other train, the bird flies directly back to the first train, and so forth. What is the total distance the bird travels before the two trains collide?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The equations of motion:
One of trains: x 1 = V 1 × t 1
The other train: x 2 = V 2 × t 2
When the trains collide, t 1 = t 2 = t ,And we get: x 1 + x 2 = 6 0 ⇔ t × ( V 1 + V 2 ) = 6 0 ⇒ t = V 1 + V 2 6 0 = 3 0 + 3 0 6 0 = 1 ( h )
And, the time travel of the bird = the time travel of the trains. So, the total distance the bird travels: S = V 3 × t = 6 0 × 1 = 6 0 ( k m )
Problem Loading...
Note Loading...
Set Loading...
it takes exactly one hour for the trains separated 60 km and moving opposite to each other at 30 kmph, velocity of bird was give as 60 kmph so it covers 60 km in an hour