Each of the dots is filled by a number from
to
. No digit is repeated.
Find the sum of the digits of the last row (the final answer).
This problem is a part of my set Numbers in Disguise - Cryptarithms .
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Didn't read the question properly. If the numbers are from 0 to 9 , there will be 4 solutions with 2 final results.
\[\begin{array} {} & 1 & 7 &&& \color{blue}{1} & \color{blue}{7} &&& 1 & 8 &&& 3 & 8 \\ \times & & 2 & & \color{blue}{ \times} & & \color{blue}{4} & & \times & & 2 & & \times & & 2 \\ \hline & 3 & 4 &&& \color{blue}{6} & \color{blue}{8} &&& 3 & 6 &&& 7 & 6 \\ + & 5 & 6 & & \color{blue}{ +} & \color{blue}{2} & \color{blue}{5} & & + & 5 & 4 & & + & 1 & 4 \\ \hline & 9 & 0 & && \color{blue}{9} & \color{blue}{ 3} && & 9 & 0 & && 9 & 0 \end{array} \]