The Efficient Bug

Geometry Level 5

A bug wants to walk from one vertex to the opposite vertex of an icosahedron in the most efficient way, and must stay on the surface.(i.e. At no time can it delve into the icosahedron's interior.)

The edges of the icosahedron have unit length.

If the minimum distance the bug must travel is x x , what is x 2 x^2 ?


Try more questions on Platonic Solids .

Image credit: http://home.btconnect.com/

Check out my other problems


The answer is 7.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Geoff Pilling
Apr 18, 2016

If you flatten out the icosahedron, like this...

You can see that the minimum distance is from a point on the top, to a point on the bottom, which has an ( x , y ) (x,y) offset of ( 0.5 , 1.5 3 ) (0.5,1.5\sqrt3) . So the distance, x x , is given by, x 2 = ( 0.5 ) 2 + ( 1.5 3 ) 2 = 7 x^2 = (0.5)^2 + (1.5\sqrt3)^2 = 7 .

x^2 isnt exactly equal to 7, it is equal to 7.46... The question should have specified to write the integer part only..

Silver Vice - 5 years, 1 month ago

Log in to reply

Wait... How do you get 7.46.... ? 0.5^2 + (1.5sqrt(3))^2 = 0.25 + 6.75 = 7

Geoff Pilling - 5 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...