The Elongated Arc

A projectile is shot at t = 0 t=0 on an infinite horizontal plane with a speed u u at an angle θ \theta to the horizontal. The coefficient of restitution between the projectile and the ground is e 1 e \neq 1 . If L 0 L_0 is the total arc length traversed by the projectile till t = t 0 t=t_0 and β \beta is the angle of projection such that L 0 L_0 is maximized , evaluate β \displaystyle \lfloor \beta \rfloor .

Details and Assumptions:

  • u u is a constant while θ \theta can vary.

  • t 0 t_0 is the time beyond which the projectile only has a velocity parallel to the ground i.e., t t 0 \displaystyle \forall t \geq t_0 , velocity of projectile has only a horizontal component.

  • Neglect all forces other than that due to gravity.

  • β \beta is an acute angle measured in degrees.


The answer is 56.

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1 solution

Guys, It's exactly the same thing as here

It can be solved using Newton's Method to find the angle which is in turn very tedious to solve

Kunal Gupta - 6 years, 8 months ago

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