The Very Long Sequence!

What is

10000 9998 9996 9994 9992 9990 . . 9990 9992 9994 9996 9998 10000 10000\cdot9998\cdot9996\cdot9994\cdot9992\cdot9990\cdot..\cdot-9990\cdot-9992\cdot-9994\cdot-9996\cdot9998\cdot10000


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Micah Gadbois
Jul 19, 2017

Since Eventually the numbers will go down to 0, the answer is 0

A previous version of this problem, as stated by @Pi Han Goh's comment (you can access it by clicking on "View reports" in the orange box) multiplies the even natural numbers from 10000 10000 to -\infty . Since in that version of the problem, the numbers extend to - \infty , the problem can be reduced to multiplying 0 0 * -\infty which is an undefined result.

Note: The problem has since been altered into its present wording.

Toby M - 3 years, 10 months ago
Toby M
Jul 19, 2017

This question is phrased quite unclearly, so the answer cannot be verified until the author does. However, if the author means to "find the product of the even integers", we can solve the question as follows:

Since 0 0 is an even integer, the product of 0 0 and ( 10000 9998 9996 ) ( 2 0 2 ) ( 9998 10000 10002 ) = 0 (10000 \cdot 9998 \cdot 9996) \cdots \cdot (2 \cdot 0 \cdot -2) \cdots (-9998 \cdot -10000 \cdot -10002) \cdots = 0 , since 0 n = 0 0 \cdot n = 0 is an identity and holds for all values of n n .

Therefore, combining these two facts gives the answer 0 0 .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...