The exponential constants

Evaluate 0^x+x^0+1^x, where x>0.

3 0 2 4 1

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2 solutions

Mahdi Raza
Jun 2, 2020

0 x = 0 x 0 = 1 1 x = 1 0 + 1 + 1 3 {\color{#20A900}{0^x = 0}} \quad \quad {\color{#D61F06}{x^0 = 1}} \quad \quad {\color{#3D99F6}{1^x = 1}} \\ \downarrow \\ {\color{#20A900}{0}} \quad + \quad {\color{#D61F06}{1}} \quad + \quad {\color{#3D99F6}{1}} \\ \downarrow \\ \boxed{3}

Let's look at the original equation. We are asked to find 0^x+x^0+1^x. The addend's in the equation are 0^x, x^0, and 1^x Soling all 3 we get:

0^x=0

x^0=1

1^x=1

Adding we get: 0+1+1=2

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