The Expression of Hurdle

A small block of mass m m is kept on a rough inclined surface of inclination θ \theta fixed in an elevator. The elevator start going up with a uniform velocity v v at t = 0 t=0 and the block does not slide on the incline.

Find the work done by the friction force on the block in t t time.

0 m g v t c o s 2 θ mgvt cos^{2}\theta m g v t s i n ( 2 θ ) mgvtsin(2\theta) m g v t s i n 2 θ mgvt sin^{2}\theta

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1 solution

Akshat Sharda
Jan 19, 2018

As the block goes up with a uniform velocity, the net force on the block is zero. So, balance forces along the incline to get, f = m g sin θ |\vec{f}|=mg\sin\theta . Displacement ( s ) (\vec{s}) will be v t vt in t t time. Also, note that angle between friction force and displacement is 90 ° θ 90°-\theta .

Therefore,

W f = f . s = ( m g sin θ ) ( v t ) cos ( 90 ° θ ) = m g v t sin 2 θ W_{f}=\vec{f}.\vec{s}=(mg\sin\theta)(vt)\cos(90°-\theta)=mgvt\sin^{2}\theta

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