Semicircle Squeeze

Geometry Level 2

Two small semicircles are inscribed in a larger semicircle, and a circle is drawn such that it is internally tangent to all three semicircles, as seen above. If the diameter of the biggest semicircle is 12, find the radius of the small circle.


The answer is 2.

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2 solutions

By using Pythagorean Theorem, we can conclude that

( 6 r ) 2 + 3 2 = ( 3 + r ) 2 (6-r)^2 + 3^2 = (3 +r)^2

36 12 r + r 2 + 9 = 9 + 6 r + r 2 36 - 12r + r^2 + 9 = 9 + 6r + r^2

36 = 18 r 36 = 18r

r = 2 r = 2

Just did it in seconds.... Note: Radius of smaller circle ( r ) = 1 6 of Diameter of bigger circle . \text{Radius of smaller circle}(r)=\frac{1}{6} \text{of Diameter of bigger circle}.

r = 1 6 × 12 = 2 . \Rightarrow r=\frac{1}{6}×12=\boxed{2}.

A Former Brilliant Member - 5 years, 4 months ago

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Nice other solution

Keep it up

Jason Chrysoprase - 5 years, 4 months ago

Yes, this works! Can you prove it?

Michael Fuller - 5 years, 4 months ago

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Yes, This can be proved in the same way as Jason did.

In right-angled \triangle .

Using Pythagoras.

( d 4 + r ) 2 = ( d 4 ) 2 + ( d 2 r ) 2 \Rightarrow (\frac{d}{4}+r)^2=(\frac{d}{4})^2+(\frac{d}{2}-r)^2

r 2 = d 4 r \Rightarrow \frac{r}{2}=\frac{d}{4}-r

r = d 6 . \therefore \boxed{r=\frac{d}{6}}.

A Former Brilliant Member - 5 years, 4 months ago

In response to abhay you can not judge it like that

Arun Garg - 5 years, 2 months ago

But how its a right angle traingle?

Yash Tripathi - 5 years, 4 months ago

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Okk got it!!

Yash Tripathi - 5 years, 4 months ago

Big thanks

Arun Garg - 5 years, 2 months ago
Kamalpreet Singh
Feb 2, 2016

Use Pythagoras theorem

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