The finale of these unoriginal problems, yay!

Algebra Level 2

I don't create this problem. All of the credits go to Nguyễn Tất Thu, Đoàn Quốc Việt and Vũ Công Minh for writing these problems, and the books in general.

This is two problems combined into one, from two different books.

a a , b b , c c , x x , y y , z z are real numbers such that a a and b b are non-negatives and

{ 5 ( 4 c 3 a 2 b ) = 3 b + 7 c 2 a = 20 y z + z x + 3 x + y = y z + 2 z x + 5 x = 1 \large \left\{ \begin{aligned} 5(4c - 3a - 2b) = 3b + 7c - 2a &= 20\\ yz + zx + 3x + y = yz + 2zx + 5x &= 1\\ \end{aligned} \right.

Let M = 2 c 2 + a 2 + 3 a b + 4 b c M = 2c^2 + a^2 + 3ab + 4bc and N = x y ( z + 2 ) N = xy(z + 2) .

Calculate the value of the following expression.

(MinM + MaxN)(MaxM + MinN) + (MaxN + MinN) \large \text{(MinM + MaxN)(MaxM + MinN) + (MaxN + MinN)}


The answer is 1164.25.

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