Two trains 100 km apart each travel towards each other at 10 km per hour. A bumblebee starts flying back and forth between the two trains at 60 km per hour, until the two trains crash into each other. What is the total distance traveled by the bumblebee?
Note: Enter number only, without units.
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Since the trains are both travelling at the same speed, hence they will crash into each other halfway. Hence, 100/2=50. This is the distance covered by the trains when they crash. By: 10=50/t, we can say that the time takes for trains to crash is 5 hours. Hence this is the time taken for the bumblebee to travel. Therefore: 60= D/5, and the distance travelled by the bee is 300.
t = 1 0 5 0 = 5 hrs
d = 6 0 × 5 = 3 0 0 km
Can u please explain it properly I don't get ur ans
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Each train simultaneously travels 2 1 0 0 = 5 0 km towards each other till they meet in the middle.
∴ the total travel time t = 1 0 5 0 = 5 hrs .
∴ the bumblebee travels back and forth between the two trains for a total of 5 hrs at 6 0 km/h
∴ the total distance covered by the bumblebee d = 6 0 × 5 = 3 0 0 km
This is a very complicated sounding problem with a very simple algebraic solution :-)
When they crash, they have covered the whole distance of 100km. They take 5 hours. Thr bumblebee flies 300km in 5 hours.
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Since the two trains have the same speed, they will collide at the center (50 km from the starting point). So the number of hours to collide is
t = 1 0 5 0 = 5
And the total distance traveled by the bee is
d = 6 0 ( 5 ) = 3 0 0 k m