and from the axle. Initially the stoppers touch the walls without being compressed. Then force of magnitude is applied perpendicular to the rod at a distance from the axle. Find the magnitude of the force compressing Stopper A.
Figure above is an overhead view of a rigid rod that turns about a vertical axle until the identical rubber stoppers A and B are forced against rigid walls at distancesLiked it? try some more
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This problem should accept the answer of 118!
Here's the solution:
You have the torque equation:
F R = f a r a + f b r b
Let's say the rod moves through an angle d θ when the stoppers are compressed. Now let's assume the force from the stoppers is proportional to the distance that they are compressed.
That gives us: k r a d θ = f a and k r b d θ = f b
But since they are identical, they will have the same constant of proportionality ( k ) so you get the relationship:
r a f a = r b f b
Now you have two equations and two unknowns so you can solve for f a and f b like any other system of equations.
I won't show the algebra, but you will find that f a , to the nearest integer, is 118N.
If you round it to the correct number of significant digits, then you get 120N